1/2(x-4)^+2=10

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Solution for 1/2(x-4)^+2=10 equation: 



1/2(x-4)^+2=10

We move all terms to the left:

1/2(x-4)^+2-(10)=0



Domain of the equation: 2(x-4)^!=0

x∈R



We add all the numbers together, and all the variables

1/2(x-4)^-8=0

We multiply all the terms by the denominator


-8*2(x-4)^+1=0

Wy multiply elements

-16x(x+1=0

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